2x^2-3y^2=3

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Solution for 2x^2-3y^2=3 equation:


Simplifying
2x2 + -3y2 = 3

Solving
2x2 + -3y2 = 3

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '3y2' to each side of the equation.
2x2 + -3y2 + 3y2 = 3 + 3y2

Combine like terms: -3y2 + 3y2 = 0
2x2 + 0 = 3 + 3y2
2x2 = 3 + 3y2

Divide each side by '2'.
x2 = 1.5 + 1.5y2

Simplifying
x2 = 1.5 + 1.5y2

Reorder the terms:
-1.5 + x2 + -1.5y2 = 1.5 + 1.5y2 + -1.5 + -1.5y2

Reorder the terms:
-1.5 + x2 + -1.5y2 = 1.5 + -1.5 + 1.5y2 + -1.5y2

Combine like terms: 1.5 + -1.5 = 0.0
-1.5 + x2 + -1.5y2 = 0.0 + 1.5y2 + -1.5y2
-1.5 + x2 + -1.5y2 = 1.5y2 + -1.5y2

Combine like terms: 1.5y2 + -1.5y2 = 0.0
-1.5 + x2 + -1.5y2 = 0.0

The solution to this equation could not be determined.

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